Bianca Andreescu defeated Angelique Kerber in the final, 6–4, 3–6, 6–4 to win the women's singles tennis title at the 2019 Indian Wells Open. It was her first WTA Tour title, and she was the first wildcard champion in tournament history. This marked the second consecutive year when a player won the tournament as her first WTA Tour singles title.
Naomi Osaka was the defending champion, but lost to Belinda Bencic in the fourth round. Osaka retained the world No. 1 singles ranking despite failing to defend her title. Petra Kvitová, Simona Halep, Sloane Stephens and Karolína Plíšková were also in contention for the top ranking.
Seeds All seeds received a bye into the second round.
Draw
Finals
Top half
Section 1
Section 2
Section 3
Section 4
Bottom half
Section 5
Section 6
Section 7
Section 8
Qualifying
Seeds
Qualifiers
Draw
First qualifier
Second qualifier
Third qualifier
Fourth qualifier
Fifth qualifier
Sixth qualifier
Seventh qualifier
Eighth qualifier
Ninth qualifier
Tenth qualifier
Eleventh qualifier
Twelfth qualifier
References
External links Main draw Qualifying draw