The 1940 United States presidential election in Rhode Island took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.
Rhode Island was won by incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of New York. Roosevelt ran with former Secretary of Agriculture Henry A. Wallace of Iowa as his running mate, and Willkie ran with Senator Charles L. McNary of Oregon.
Roosevelt won Rhode Island by a margin of 13.56%. The state became one of five that shifted left from 1936, alongside Maine, New Hampshire, North Carolina, and Vermont.Dave Leip's Atlas of U.S. Presidential Elections; 1940 Presidential General Election Data -- National
Results
By county 1940 United States presidential election in Rhode Island (by county)CountyFranklin D. RooseveltDemocraticWendell WillkieRepublicanOther candidatesVarious partiesMargin Total % # % # % # % ##Bristol 52.9% 5,967 47.1% 5,314 0.03% 3 5.8% 653 11,284Kent 49.2% 14,333 50.7% 14,790 0.1% 28 -1.5% -457 29,151Newport 51.8% 10,645 48.1% 9,882 0.1% 14 3.7% 763 20,541Providence 59.3% 145,236 40.6% 99,434 0.1% 251 18.7% 45,802 244,921Washington 39.3% 6,001 60.5% 9,233 0.1% 17 -21.2% -3,232 15,251
See also United States presidential elections in Rhode Island
References