A presidential election was held in Illinois on November 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 9.38%.
Harrison won Chicago by six votes.
Results 1836 United States presidential election in IllinoisPartyCandidateVotesPercentageElectoral votes Democratic Martin Van Buren 18,369 54.69% 5 Whig William Henry Harrison 15,220 45.31% 0 Totals 33,589 100.0% 5
See also United States presidential elections in Illinois
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