A presidential election was held in Arkansas on November 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Arkansas, having been admitted to the Union as the 25th state on June 15, 1836, voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White during its first presidential election. Van Buren won Arkansas by a margin of 28.16%.
Results 1836 United States presidential election in ArkansasPartyCandidateVotesPercentageElectoral votes Democratic Martin Van Buren 2,380 64.08% 3 Whig Hugh White 1,334 35.92% 0 Totals 3,714 100.00% 3
Results By County +1836 United States Presidential Election in Arkansas (By County)CountyMartin Van BurenDemocraticHugh Lawson WhiteWhigTotal#%#%Arkansas3831.67%8268.33%120Carroll7392.41%67.59%79Chicot4345.74%5154.26%94Clark4185.42%714.58%48Conway2332.39%4867.61%71Crawford10947.81%11952.19%228Crittenden3858.46%2741.54%65Hempstead11056.99%8343.01%193Hot Spring1168.75%531.25%16Independence13454.25%11345.75%247Izard8785.29%1514.71%102Jackson5653.85%4846.15%104Jefferson5051.02%4848.98%98Johnson10772.79%4027.21%147Lafayette3073.17%1126.83%41Lawrence8272.57%3127.43%113Monroe1732.69%3567.31%52Phillips9659.63%6540.37%161Pike33100.00%00.00%33Pope9366.91%4633.09%139Pulaski23455.06%19144.94%425Randolph13889.03%1710.97%155Saline8160.90%5239.10%133Sevier6766.34%3433.66%101St. Francis10885.71%1814.29%126Van Buren1967.86%932.14%28Washington62282.38%13317.62%755White1736.96%2963.04%46Totals2,38064.08%1,33435.92%3,714
See also United States presidential elections in Arkansas
References