The 1824 United States presidential election in Kentucky took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. Kentucky voted for Henry Clay over Andrew Jackson, John Quincy Adams, and William H. Crawford. Clay won Kentucky, his home state, by a wide margin of 43.46%.
Kentucky was divided into three electoral districts for this election, with electors chosen through block voting. District 1 elected four electors, while Districts 2 and 3 elected five electors each.
Results 1824 United States presidential election in KentuckyPartyCandidateVotesPercentageElectoral votes Democratic-Republican Henry Clay 17,207 71.73% 14 Democratic-Republican Andrew Jackson 6,658 27.76% 0 Democratic-Republican John Quincy Adams 120 0.50% 0 Democratic-Republican William H. Crawford 3 0.01% 0 Totals 23,988 100.0% 14
Results by electoral district +Results by DistrictDistrictHenry ClayDemocratic-RepublicanAndrew JacksonDemocratic-RepublicanJohn Quincy AdamsDemocratic-RepublicanWilliam H. CrawfordDemocratic-RepublicanMarginTotal votescast#%Electors#%Electors#%Electors#%Electors#%13,86171.47%41,47327.27%0651.20%030.06%02,32042.94%5,40226,16569.46%52,71130.54%0 no candidates no ballots 3,454 38.92%8,87637,18173.95%52,47425.48%0550.57%0 no candidates 4,652 47.90%9,710Total17,20771.73%146,65827.76%01200.50%030.01%010,42643.46%23,988
See also United States presidential elections in Kentucky
References