In mathematics, an Euler–Cauchy equation, also known as a Cauchy–Euler equation, equidimensional equation, or Euler's equation, is a linear ordinary differential equation for which the homogeneous part is invariant under changes to the scale of its independent variable. Euler was the first we know of to study equations of this form in the early 1700's, with a notable appearance in Institutiones calculi integralis, volume 2 in 1768.

The equation

Let be the nth derivative of the unknown function . Then a Cauchy–Euler equation of order n has the form

The substitution (that is, ; for , in which one might replace all instances of by , extending the solution's domain to ) can be used to reduce this equation to a linear differential equation with constant coefficients. Alternatively, the trial solution can be used to solve the equation directly, yielding the basic solutions.

Second order – solving through trial solution

The most common Cauchy–Euler equation is the second-order equation, which appears in a number of physics and engineering applications, such as when solving Laplace's equation in polar coordinates. The second order Cauchy–Euler equation is

We assume a trial solution

Differentiating gives and

Substituting into the original equation leads to requiring that

Rearranging and factoring gives the indicial equation

We then solve for m. There are three cases of interest:

Case 1 of two distinct roots, and ; Case 2 of one real repeated root, ; Case 3 of complex roots, .

In case 1, the solution is

In case 2, the solution is

To get to this solution, the method of reduction of order must be applied, after having found one solution .

In case 3, the solution is

For .

This form of the solution is derived by setting and using Euler's formula.

Second order – solution through change of variables

We operate the variable substitution defined by

Differentiating gives

Substituting the differential equation becomes

This equation in is solved via its characteristic polynomial

Now let and denote the two roots of this polynomial. We analyze the case in which there are distinct roots and the case in which there is a repeated root:

If the roots are distinct, the general solution is where the exponentials may be complex.

If the roots are equal, the general solution is

In both cases, the solution can be found by setting .

Hence, in the first case, and in the second case,

Second order - solution using differential operators

Observe that we can write the second-order Cauchy-Euler equation in terms of a linear differential operator as where and is the identity operator.

We express the above operator as a polynomial in , rather than . By the product rule, So,

We can then use the quadratic formula to factor this operator into linear terms. More specifically, let denote the (possibly equal) values of Then,

It can be seen that these factors commute, that is . Hence, if , the solution to is a linear combination of the solutions to each of and , which can be solved by separation of variables.

Indeed, with , we have . So, Thus, the general solution is .

If , then we instead need to consider the solution of . Let , so that we can write As before, the solution of is of the form . So, we are left to solve We then rewrite the equation as which one can recognize as being amenable to solution via an integrating factor.

Choose as our integrating factor. Multiplying our equation through by and recognizing the left-hand side as the derivative of a product, we then obtain

Example Given

we substitute the simple solution :

For to be a solution, either , which gives the trivial solution, or the coefficient of is zero. Solving the quadratic equation, we get . The general solution is therefore

Difference equation analogue There is a difference equation analogue to the Cauchy–Euler equation. For a fixed , define the sequence as

Applying the difference operator to , we find that

If we do this times, we find that

where the superscript denotes applying the difference operator times. Comparing this to the fact that the -th derivative of equals

suggests that we can solve the N-th order difference equation

in a similar manner to the differential equation case. Indeed, substituting the trial solution

brings us to the same situation as the differential equation case,

One may now proceed as in the differential equation case, since the general solution of an -th order linear difference equation is also the linear combination of linearly independent solutions. Applying reduction of order in case of a multiple root will yield expressions involving a discrete version of ,

(Compare with: )

In cases where fractions become involved, one may use instead (or simply use it in all cases), which coincides with the definition before for integer .

See also Hypergeometric differential equation Cauchy–Euler operator

References

Bibliography