Clock angle problems are a type of mathematical problem which involve finding the angle between the hands of an analog clock.
Math problem Clock angle problems relate two different measurements: angles and time. The angle is typically measured in degrees from the mark of number 12 clockwise. The time is usually based on a 12-hour clock.
A method to solve such problems is to consider the rate of change of the angle in degrees per minute. The hour hand of a normal 12-hour analogue clock turns 360° in 12 hours (720 minutes) or 0.5° per minute. The minute hand rotates through 360° in 60 minutes or 6° per minute.
Equation for the angle of the hour hand
where: is the angle in degrees of the hand measured clockwise from the 12 is the hour. is the minutes past the hour. is the number of minutes since 12 o'clock.
Equation for the angle of the minute hand
where: is the angle in degrees of the hand measured clockwise from the 12 o'clock position. is the minute.
Example The time is 2:20. The angle in degrees of the hour hand is:
The angle in degrees of the minute hand is:
Equation for the angle between the hands The angle between the hands can be found using the following formula:
where is the hour is the minute If the angle is greater than 180 degrees then subtract it from 360 degrees.
Example 1 The time is 2:20.
Example 2
The time is 10:16.
When are the hour and minute hands of a clock superimposed?
The hour and minute hands are superimposed only when their angle is the same.
is an integer in the range 0–11. This gives times of: 0:00, 1:05., 2:10., 3:16., 4:21., 5:27.. 6:32., 7:38., 8:43., 9:49., 10:54., and 12:00. (0. minutes are exactly 27. seconds.)
See also Clock position
References
External links https://web.archive.org/web/20100615083701/http://delphiforfun.org/Programs/clock_angle.htm http://www.ldlewis.com/hospital_clock/ - extensive clock angle analysis https://web.archive.org/web/20100608044951/http://www.jimloy.com/puzz/clock1.htm